+1Hi
I have 2 transformers (A and B) they have to provide a Sorter with inputs.
If there isn’t any output from A, then this workflow C has to stop, but not the entire workspace.
If there is output from both A and B, it has to continue.
If there is only output from A and not B, it has to contiunue.
Is it possible?
Best answer by virtualcitymatt
My favorite to use the the FeatureFlowValve custom transformer. Inside it’s essentially just a FeatureMerger with 1==1 but I like it because I can choose whether it opens or closes what does through the Input
In this case A is the ValueControl and features will only go through in the case there is a feature coming out of ‘A’
+35This is a double solution:
For a single solution like in your case you can stop after the FeatureMerger_3 in this example.
The Sampler is set to N=1. The Keeper to nothing and the FeatureMerger is set to merge on Requestor=1 Supplier=1.
+7How about this? put a 1 in both the key fields for the attribute merger. depending on the schema you may need to remove extra attributes from the merge fields so it only matches the requestors schema.
+47My favorite to use the the FeatureFlowValve custom transformer. Inside it’s essentially just a FeatureMerger with 1==1 but I like it because I can choose whether it opens or closes what does through the Input
In this case A is the ValueControl and features will only go through in the case there is a feature coming out of ‘A’
+1Thank you very much for all the answers. The last one, where “FeatureFlowValve” was used, is perfect for the purpose. However, the other methods also worked :)
+59I thought it was time that we had a better solution for this type of scenario, so I created the DataLogicController transformer and uploaded it to the FME Hub.
I added a description to the latest What’s Up Wednesday newsletter.
Basically, for this scenario, the setup would look like this:
The logic to use is called “Projection”. It’s also capable of doing AND (must have both A and B data), OR (only needs one set of data), and a host of other logical operations.
I hope you find this interesting (even if you have a solution already).
Mark
