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how to cancel point that intersected between five paths and consider the paths is not connected

  • March 27, 2020
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gogopotter90
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i have 5 pathes of lines and they intersected in one point and each path has 4 connected lines and each lines has his own id .

when i use network topology uilder by id ,i find it considers all lines in all paths as connected has the same value of network id

 

i want to work on each 5 paths but as not connected in one point ,how could i do that .

i mean ,as first path that has 4 connected lines and each lines in this path connected till the point that intersected with another paths

i want to consider 4 lines in each path as conneced but not connects with another path

i do not want to consider every path that includes lines as connected to other paths .i want to make each path as seperated ,how could i do that.Thanks

 

Best answer by gio

@gogopotter

hi,you can use edge output as it has a to and form node. You can merge on node_id.

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3 replies

gio
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  • March 27, 2020

@gogopotter90

 

If you have pushed your lines trough a TopologyBuilder you will get a list called node_angle{}.

Use listelementcounter on this list.

result 1 is endnode (i believe this is what you are looking for), >1 is ok node and rest is wrong

 

Iuse this test to manaualy correct networks during networkbuilding etc...(in fact i was just doing it again)

 

Greetz!


gio
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  • March 27, 2020

@gogopotter90

 

 

to be correct >2 is correct.

As =2 can be a "in-line" node which is not correct for a network. Can indicate a drawing errro for instance.

As are 2 endnodes close together; likely drawing error.

etc.


gio
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  • March 28, 2020

@gogopotter

hi,you can use edge output as it has a to and form node. You can merge on node_id.