Can I use String replacer to add a character between two regular expessions?

Question

Hello,

I need to reformat some strings.

3/2-A1 needs to become 3/2-A01. Where I have a dash followed by a letter followed by a number I want to replace it by dash, the same letter, 0, then the same number.

I can find my string using a regular expression :

->A-Z]Z1-9]

and I've tried - A-Z]0]1-9] in the Replacement text box of String Replacer but (unsurprisingly that just gives me

3/2-2A-Z]0]1-9]

Is there away to search for the whole regex, but only replace part of it?

Page 1 / 1

text to match: (-[A-Z])([1-9])

replacement text: \\10\\2

putting parentheses around sections creates parts, and then you can refer to the parts as \\1, \\2 etc.

Reply

jdh · Answer

text to match: (-[A-Z])([1-9])replacement text: \10\2putting parentheses around sections creates parts, and then you can refer to the parts as \1, \2 etc.

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