Find road facing Building

This questions seems a bit broad, could you clarify what you are looking for?

In particular, how are you defining sides? Looking at the image I see what appears to be 2 segments that make up the “red side”, more importantly in the yellow and purple “sides” you have 2 segments highlighted that are disjoint and separated by segments that you have not highlighted. This task may require generalization of the input polygon to some degree depending on your definitions of “side”.

WIthout knowing more, the workspace could give greatly different results. But I suppose this could maybe help you:

1. bounding box over the house shape
2. Chopper á 2 vertices on the bouding box
   and now for the tricky part to get the closest road in a 90° angle from the midpoint of each side (at least that’s how I interpreted what you want):
3. centerpoint extractor
4. rotator with 90° around each extracted centerpoint
5. looper with ‘line extender’ until ‘line on line overlayer’ has a result

Though you would still have to cover some special cases like: 

• as line extender extends in both directions you want the road facing away from the bounding box (maybe a filter on y/x coordinates beforehand could help here)
• if the roads or building is placed differently (e.g. building a bit to the right) he would find the same line on both sides (here the yellow one for north and east)
  ​​​​​

I bet there are even better ways, but I hope this helps at least a bit as it would work on your given example at least.

I agree ​@haverm, I was thinking of something along the same lines as you with steps 2-4. I think those steps could also be applied on a generalized shape effectively as well.

​@boubcher I think a defined max distance would be helpful.

geomancer wrote:

A variant of the process mentoned above:

1. Create a bounding box over the house shape
2. Create lines of 2 vertices from the bouding box with a Chopper
3. Create a perpendicular line to one side, through the midpoint of each line
4. intersect with the roads
5. find the nearest intersection for each line

For creating the perpendicular lines I used the 2DVectorCalculator from FME Hub.

​@geomancer 
Thanks  I did some adjustment to fit the Geometry Shape