+15Hi, I am using a PythonCaller to create an XML string. When I send this string through an XMLTemplater, all "<>" brackets are converted to "<" and ">" (html encodings). Adding a StringReplacer/StringPairReplacer to replace all brackets works fine but can take some time for larger content . Is there a way to prevent the XMLTemplater from converting brackets to encoded brackets?
becomes:
Best answer by takashi
Hi @Jasper Wisbecq , in this case, this template (XQuery) expression would work.
<Asset>{
for $x in tokenize(fme:get-attribute("output"),'\s')
return parse-xml($x)
}</Asset>
+32If you want to insert an xml fragment into the xml template you need to use {fme:get-xml-attribute("xml")}. For this to work however, it needs to be a valid xml fragment which your example is not
Hi @Jasper Wisbecq , in this case, this template (XQuery) expression would work.
<Asset>{
for $x in tokenize(fme:get-attribute("output"),'\s')
return parse-xml($x)
}</Asset>
+32Hi @Jasper Wisbecq , in this case, this template (XQuery) expression would work.
<Asset>{
for $x in tokenize(fme:get-attribute("output"),'\s')
return parse-xml($x)
}</Asset>
These are the sort of examples that all need to be gathered up and put in the helpfiles as I mentioned @Dale Lutz
+15If you want to insert an xml fragment into the xml template you need to use {fme:get-xml-attribute("xml")}. For this to work however, it needs to be a valid xml fragment which your example is not
If I add a root node to the fragment, the get-xml-attribute works perfectly indeed. However, for my particular case, the root node is undesired, and I would need a StringReplacer to remove it again after the XMLTemplater. Though this would already be much faster than having to replace all brackets, the solution of @Takashi Iijima suits even better
+15Hi @Jasper Wisbecq , in this case, this template (XQuery) expression would work.
<Asset>{
for $x in tokenize(fme:get-attribute("output"),'\s')
return parse-xml($x)
}</Asset>
Great, thank you Takashi
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