PythonCaller - variable as buffer

Question

I would like to implement a variable as a buffer. However, once I define the variable, it does not get updated.

For example:

The variable has to act like a buffer.. At the moment, I have the variable implemented in the def but I think this is wrong.

def buffer(feature):

puffer = 'leer'

for i in range(0,50):

if puffer == 'leer':

feature.setAttribute('value', value2)

puffer = 'value2'

else:

feature.setAttribute('value', value3)

For this example, I get always the Result from feature.setAttribute('value', value2).

I have also tried to create a class withdef __init__(self) and Input and close.

But I don't get a Result.The result should be written in the attribute table of a shapefile

Can anyone help me?

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You'll have to write your code according to the expectations of FME. Otherwise your code might not be called by FME at all.

PS: next time, please post your code using the Code Snippet formatting tool, so that indentations are preserved.

david_r · Answer

You'll have to write your code according to the expectations of FME. Otherwise your code might not be called by FME at all.

PS: next time, please post your code using the Code Snippet formatting tool, so that indentations are preserved.

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