Hi all,
I’m new to FME and would like to know if there is a way to generate a v5 UUID in FME 2024? From what I have read I can’t see a method for this.
Thanks.
Solved
Version 5 UUID
+1- Contributor
Best answer by hkingsbury
You could make use of a python caller and uuid.uuid5()
https://docs.python.org/3/library/uuid.html#uuid.uuid5
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+43- Influencer
https://support.safe.com/hc/en-us/articles/25407440578189-Creating-a-Unique-Identifier-CRCCalculator
I don’t know about official v5 but this should give you something similar. Do you think this would work?
+1- Contributor
Thanks for the reply. I looked at CRC but I need the value to be in UUID format to satisfy downstream requirements.
+64- Celebrity
- Best Answer
You could make use of a python caller and uuid.uuid5()
https://docs.python.org/3/library/uuid.html#uuid.uuid5
+28- Influencer
I was curious, so I’ve made a CT for that (but on FME 2025 tho 😅)
https://hub.safe.com/publishers/abizien/transformers/uuidv5generator
Draw it, map it, shape it, fix it, share it, change it, send, translate it 🎵