When dealing with features in a 3D space though, distance and direction are not enough. Additionally, the distance will be different by measuring to the inclined feature rather than across on a 2D plane.
Is there a way to do this?
Thanks in advance,
Matt
one solution might be to replace each feature with a 3D point, use the ElevationExtractor to get the Z-values, connect the points and then use a LengthCalculator (dimension: 3) to get the length in 3D space.
The inclination can then be found with something like tan? = (Za - Zb) / length.
David
Regards
Matt
Since it's easy to make a mistake in using trigonometric functions, re-confirm carefully the definition of those. I also sometimes get confused ;-)
Takashi
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