Hi ​@deanhowell 

I am curious how to do this as well. Seems like it is taking the whole list and writing out as one line where we want it create a record set of pairs. if we did this by hand we would do something like:

{
  "name": fme:get-list-attribute("JSONList{0}.JSONname"),
  "value": fme:get-list-attribute("JSONList{0}.JSONvalue")
}
{
  "name": fme:get-list-attribute("JSONList{1}.JSONname"),
  "value": fme:get-list-attribute("JSONList{1}.JSONvalue")
}

But we want it to iterate through the list like:

{
  "name": fme:get-list-attribute("JSONList{n}.JSONname"),
  "value": fme:get-list-attribute("JSONList{n}.JSONvalue")
}

I am sure there is a simple straight forward solution. I will share if I get something working. Good luck!

Hi ​@deanhowell ,

A simple way is to extract elements of the JSONList{} with ListExploder beforehand, then set this expression as the SUB template in the JSONTemplator.

{
  "name": fme:get-attribute("JSONname"),
  "value": fme:get-attribute("JSONvalue")
}

rAddition] Alternatively, using XQuery syntax, this Root template expression is also possible, without using SUB expression.

{
    "publishedParameters" :
    /
        let $names := fme:get-list-attribute("JSONList{}.JSONname")
        let $values := fme:get-list-attribute("JSONList{}.JSONvalue")
        for $i in (1 to count($names))
        return
        {
            "name" : $names$$i],
            "value" : $valuesv$i]
        }
    ]
}

Thanks ​@takashi great advice as always. I was just over complicating things and had a list builder in the process, which wasn’t needed.