$ curl -X POST --noproxy “*” -k "https://server_name/connect/token" -H "Content-Type: application/x-www-form-urlencoded" -d "username=asdfg" -d "password=ghjkl" -d "client_id=CLIENT_ID" -d "client_secret=CLIENT_SECRET" -d "scopes=openid profile role" -d "grant_type=password"
Page 1 / 1
Curl is meant to be run from the command line, not through HTTPCaller.
The SystemCaller may be of help here.
you can use python caller also to do this
import urllib2
data = '{"nw_src": "10.0.0.1/32", "nw_dst": "10.0.0.2/32", "nw_proto": "ICMP", "actions": "ALLOW", "priority": "10"}'
url = 'http://localhost:8080/firewall/rules/0000000000000001'
req = urllib2.Request(url, data, {'Content-Type': 'application/json'})
f = urllib2.urlopen(req)
for x in f:
print(x)
f.close()
you can use python caller also to do this
import urllib2
data = '{"nw_src": "10.0.0.1/32", "nw_dst": "10.0.0.2/32", "nw_proto": "ICMP", "actions": "ALLOW", "priority": "10"}'
url = 'http://localhost:8080/firewall/rules/0000000000000001'
req = urllib2.Request(url, data, {'Content-Type': 'application/json'})
f = urllib2.urlopen(req)
for x in f:
print(x)
f.close()
Thank you. I will try this
Hi @sal, check out this article which runs through how you might use the HTTPCaller to make a call using cURL: https://community.safe.com/s/article/Web-Services-cURL-and-the-HTTPCaller
Hi @sal, check out this article which runs through how you might use the HTTPCaller to make a call using cURL: https://community.safe.com/s/article/Web-Services-cURL-and-the-HTTPCaller
Thank you. It is really helpful.