Skip to main content
  • EN

Yes - another XML question - however - taking the XML below - how do I extract the values just from the 'details_view' - i.e. I want the 'USER' data. I tried the flattening which could work, but I don't know how to differentiate between the two 'views'. 

 

<?xml version="1.0" encoding="utf-8" standalone="yes"?>
<file>
      <views>
        <view type="summary_view">
          <nodes>
            <node>
              <properties>
                <property type="field_name">DATE_CREATED</property>
                <property type="field_data" year="2019" month="3" day="12" hour="11" minute="21" second="52" millisecond="938" offsetMinutes="0" normalized="True">2019-03-12T11:21:52.938+00:00</property>
              </properties>
            </node>
          </nodes>
        </view>
        <view type="details_view">
          <nodes>
            <node>
              <properties>
                <property type="field_name">USER</property>
                <property type="field_data">myusername</property>
              </properties>
            </node>
          </nodes>
        </view>
      </views>
</file>

 

Any help would be gladly received...

Ramo

If you use the XML Fragmenter you can return 2 features, one for each view. If you expose view.type you can differentiate between them

If you use the XML Fragmenter you can return 2 features, one for each view. If you expose view.type you can differentiate between them

You can also extract just your required XML element with a predicate in the Elements to Match parameter (i.e. XPath).

See here to learn more about XPath syntax: https://www.w3schools.com/xml/xpath_syntax.asp

Reply


Community Stats

29,729
Posts
112,948
Replies
37,369
Members
Terms & ConditionsCookie settings