Point Isolator

Hi Ted,

 

 

I assume there are (x, y, z) in a line of the source CSV file. But, sorry, I don't see clearly what is the condition to isolate (classify?) those points. Could you explain about that in detail a little more?

 

 

> that are divisible evenly by 0.25

 

 

Takashi

Hi,

 

 

you can check if a floating point number is evenly divisible by 0.25 using the following expression in an ExpressionEvaluator:

 

 

(round(@Value(MyFloatAttribute)*1000.0) % round(0.25*1000.0) == 0) ? 1 : 0

 

 

It will return the value 1 if it is evenly divisble by 0.25, otherwise it will return 0.

 

 

(The trick here is to convert the floats to integers to avoid accuracy problems, using a multiplier an order of magnitude larger than the resolution of our calculation, here 1000.0)

 

 

David

I got it, you want to treat every point whose z value is divisible evenly by 0.25. I missed z value...

 

  The way suggested by David would work well. And if the actual data condition allows to ignore the accuracy problems, you also can consider using @fmod function in the ExpressionEvaluator: @fmod(@Value(z),0.25)   This expression returns 0 when z is divisible evenly by 0.25. In addition, if your purpose is only to write the calculation result into a new CSV file, I don't think you need to replace the source (x, y, z) with a Point geometry using the 3DPointAdder .

 

 

Takashi

Thanks for all your help