+6Hi. I need to know how can I get data between two characters.
I have an attribute like this:
10 12 Street (Main) Camnore
Firstly I need to get data between two characters ( ) and Secondly I need to convert it into two columns with this result:
10 12 Street Camnore
10 Main Camnore
Is StringSearcher is helpful? if yes how can I get this result?
I really appreciate your assistance
Best answer by joepk
Hi, do these RegExes work in your StringSearcher?
(?<=\().*?(?=\)) This matches the word between parentheses (extracts ‘Main’)
\d+ This matches the first number of your string (extracts ‘10)
\w+$ This matches the last word of your string (extracts ‘Camnore’)
If you use 3 StringSearchers to extract these strings you can construct “10 Main Comnore” using a StringConcatenator.
You can use a StringReplacer replacing the RegEx \([^()]+\) to replace the ‘(Main)’ part with nothing, leaving you with “10 12 Street Camnore”
Hope this helps!
Edit: I am not familiar with US (?) addresses, so I'm not sure if this matches all your cases
+45
I suggest you use the transformer StringSearcher with this Regular Expression: (?<=\[).*?(?=\])
You get the result into characters.
+6Thank you for your reply danilo_fme
When I used that, I got same result as my Input. Do you have any idea?
Thank you for your time
+45Thank you for your reply danilo_fme
When I used that, I got same result as my Input. Do you have any idea?
Thank you for your time
Please, could you share your Workspace?
+6
danilo_fme The result in NotMatched is same as input like this:
10 12 Street (Main) Camnore
+20Hi, do these RegExes work in your StringSearcher?
(?<=\().*?(?=\)) This matches the word between parentheses (extracts ‘Main’)
\d+ This matches the first number of your string (extracts ‘10)
\w+$ This matches the last word of your string (extracts ‘Camnore’)
If you use 3 StringSearchers to extract these strings you can construct “10 Main Comnore” using a StringConcatenator.
You can use a StringReplacer replacing the RegEx \([^()]+\) to replace the ‘(Main)’ part with nothing, leaving you with “10 12 Street Camnore”
Hope this helps!
Edit: I am not familiar with US (?) addresses, so I'm not sure if this matches all your cases
+6Hi, do these RegExes work in your StringSearcher?
(?<=\().*?(?=\)) This matches the word between parentheses (extracts ‘Main’)
\d+ This matches the first number of your string (extracts ‘10)
\w+$ This matches the last word of your string (extracts ‘Camnore’)
If you use 3 StringSearchers to extract these strings you can construct “10 Main Comnore” using a StringConcatenator.
You can use a StringReplacer replacing the RegEx \([^()]+\) to replace the ‘(Main)’ part with nothing, leaving you with “10 12 Street Camnore”
Hope this helps!
Edit: I am not familiar with US (?) addresses, so I'm not sure if this matches all your cases
Hi joepk. Thank you so much for your time and complete answer. I only have a problem.
When I use a StringReplacer replacing the RegEx \([^()]+\) to replace the ‘(Main)’ part with nothing, it’s not working. Do you have any idea about it?
+20Yes, your StringReplacer is set to ‘Replace Text’, but you have to set it to ‘Replace Regular Expression’
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