Hi All,
Just wondering what is the best option to flatten a list on each row to attributes? I know the lists are set at the same size index wise but wondering on the best method
thanks
Depends on what "to flatten list" means. For example, if the feature has a list called "_list{}" containing these elements, what would be your desired result?
_list{0} = 'a'
_list{1} = 'b'
_list{2} = 'c'
Hi Takashi,
I would be happy with new attributes against the same parent row i.e. list0 = a, list1 = b and list2 = c.
I was looking at the exposer but thought there must be a simpler approach?
danilo_fme wrote:
I agree wit you
Does this not just create 3 rows - i need them all on the original row?
Thanks
Hi @lemzip, I think the BulkAttributeRenamer (Regular Expression Replace, Rename mode) can be used effectively here. If you exposed the list elements in the preceding transformer (Right-click on the list name - Expose Elements), the renamed attributes would be exposed automatically.
Text To Find: ^(_list){(\d+)}$ <regular expression that match every element of the list>
String: \1\2 <concatenate the parts matched sub expressions>
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