+28I often use the AttributeSplitter or other transformers to parse data and rename the resulting list elements as regular attributes.
In FME 2015, an AttributeRenamer could point to a specific list element (ie _list{1}) to rename it, this is no longer the case in FME2016.
Example
_list{0}: 45
_list{1}: 30
_list{2}: 31
would be renamed to
Degrees: 45
Minutes: 30
Seconds: 31
Best answer by takashi
The AttributeRenamer still works to rename individual list elements. You can edit the "Input Attribute" column directly. e.g. change "_list{}" to "_list{0}".
+28AttributeManager is the transformer to do this.
How?
The attributeManager allows me to rename the list, but I can't figure out how to rename the elements.
The AttributeRenamer still works to rename individual list elements. You can edit the "Input Attribute" column directly. e.g. change "_list{}" to "_list{0}".
The AttributeRenamer still works to rename individual list elements. You can edit the "Input Attribute" column directly. e.g. change "_list{}" to "_list{0}".
I updated an Idea concerning to setting list elements to the Input Attribute column of the AttributeRenamer: Allow Selecting Multiple List Elements for Old (Input) Attribute Column in AttributeRenamer
+17I updated an Idea concerning to setting list elements to the Input Attribute column of the AttributeRenamer: Allow Selecting Multiple List Elements for Old (Input) Attribute Column in AttributeRenamer
We'll dig into this. Sorry @jdh for the complication here. We'll see what we can do in 2016.1
+28See attached images:
This creates a second set of attributes rather than renaming the list, which admittedly can be removed once all the attributes have been copied, but is not the most efficient when dealing with large datasets.
+17In the same AttributeManager after copying the wanted attributes, you can remove the list. You do not need a second transformer to do that.
+15The best answer is actualy not true. And has never been.
The list will not be renamed.
You will be creating a new attribute from the listelement. The selected list attribute is removed from the list.
Check the data inspector, you will see the list is now without the selected element.
The selected element has become an attribute.
U end up with an unbalanced list...appearantly?
+28The best answer is actualy not true. And has never been.
The list will not be renamed.
You will be creating a new attribute from the listelement. The selected list attribute is removed from the list.
Check the data inspector, you will see the list is now without the selected element.
The selected element has become an attribute.
U end up with an unbalanced list...appearantly?
In this scenario, that's actually the goal. I want to turn the list into a set of independent attributes.
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