If you use the BoundsExtractor and then create a point on the _xmax and _ymin coordinates you have the down right corner of the bounding box. Plug that into a NeighborFinder along with the original geometry (and group by a unique id, use a Counter to create one if you don't have one) and then you'll get the most down-right coordinates of the original geometry as the _closest_candidate_x and _closest_candidate_y
I'm afraid it's not so simple.
The meaning of "down right corner" is not obvious. To simplify the problem, even you assume the shape is rectangle, there are at least two possible definitions for "down right corner".
Lower vertex in two right-hand vertices:
Right-hand vertex in two lower vertices:
First of all, you have to define what "down right corner" is for the actual shape, I think.
I'm afraid it's not so simple.
The meaning of "down right corner" is not obvious. To simplify the problem, even you assume the shape is rectangle, there are at least two possible definitions for "down right corner".
Lower vertex in two right-hand vertices:
Right-hand vertex in two lower vertices:
First of all, you have to define what "down right corner" is for the actual shape, I think.
You're right, my assumption is that the down right corner is the vertex that's closest to the down right corner of the feature's bounding box, but thay may indeed lead to "strange" results sometimes.
My mapsheets are on screenshot.....i rotate the layout always that mapsheet is horizontal
The right down corner from this horizontal mapsheet finally is meant.
Greetz
Franco
As long as seeing your screenshot, your desired corner seems to be "right end node of lower long side" for each rectangle. If so, assuming all the rectangles have the same size, a possible way is:
