Today is 2019-SEP-20
%Y = 2019 / Year
%b = Sep / Month
%a = Fri / Day Name
%d = 20 / Day
%u = 37 / Week of Year
??? = 3 (3rd Friday of September)
What I'm trying to find this is the 3rd Friday this month?
ie
2019-SEP-06 is the 1st Friday of September
2019-SEP-13 is the 2nd Friday of September
2019-SEP-30 is the 3rd Friday of September
2019-SEP-27 is the 4th Friday of September
Hi @hlouie
Do you if there is a python code to do this operation?
Thanks in Advance,
Danilo
Yes, but I wanted to check out pure FME first.
datetime.datetime(2011, 8, 15) // should return 3
datetime.datetime(2011, 2, 28) // should return 5
datetime.datetime(2011, 8, 29) // should return 5Hi @hlouie, I don't think there is a single function to return your required text, but you can achieve that with some FME String, Math, and Date/Time functions. e.g. assuming that an attribute called "_date" stores a date value formatted with %Y-%b-%d (e.g. "2019-SEP-20")
See these documentations to learn more about those functions.
Result:
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