+22
What method do use to parse the Filename (multiple) parameter in python?
I currently use
source = FME_MacroValues['Param1']
if source.startswith('"'):
from shlex import split
fileList = split(source[1:-1])
else:
fileList=[source] but it feels clunky.
The assumption is that if it's a single file, it is not wrapped in quotes, but if it's multiple files it is:
""file1" "file2" "file3""
+17
Hi @jdh,
You could try:
source = FME_MacroValues['Param1']
filelist = shlex.split(shlex.split(source)[0])
+17
The shlex.split method may not work as expected if a file path could contain a space, so I would use str.strip and str.split method simply. This works like the AttributeTrimmer and the AttributeSplitter.
source = FME_MacroValues['Param1']
filelist = source.strip('"').split('" "')
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