FME Desktop 2022: Disaggregating two polygons gets them unexpectedly three,

let call the two feautres you read in from the DWG, 'G1' and 'G2'

G1:G2: 

G1 is pretty simple, just a plain polygon 

G2 is a more complex geometry and has two parts a, polygon and a donut 

The polygon part of G2 is the same geometry as G1 (the red dot is the first vertex). It is by itself, a simple polygon 

The second part of G2 is also a complex geometry that has multiple parts to it. Because it is a donut it has also has two parts, the inside and the outside (lines).

So, because G1 has one part and G2 has two parts, deaggreating gets you three parts. I think whats confused you here as that there are multiple geometries representing the hole in the large geometry

I'm assuming that you're required output is the donut and the geometry . (more on that at the bottom)

FME is showing exactly what the geometry is, you mentioned that visually they're the same in CAD, but in FME they're not. This comes down to multiple factors, a lot of software and formats (CAD, ArcGIS, GDB, SDE, ArcGIS Online to name a few) will have data level precision's that default to a certain value, for 99.9% of use cases, these precision's are perfectly sufficient. (eg coordinates are rounded to 5 decimal places).

The thing with FME (to the extent of almost being a 'fault') is that it doesn't have these limits in place, if a coordinate has 10 decimal places ultimately placing it at an accuracy of a fraction of a mm, then it will do that, if you're comparing this coordinate in another piece of software that rounds it to 5 decimal places, then those two locations will be different. Again, if this coordinate exisits in a CSV and you're comparing it to the 'same' point in SDE, it is highly likely they will be 'different' yet not on a level where you can visually see it.

Back to the donut question. Because G2 contains two geometries, you can deaggregate that and use the two individual parts.

Use a PartCounter to get the counts of the number of parts, then use a tester to find which one has more than two parts. Then deaggregating the result will leave you with two geometries - the smaller polygon and the larger donut

Are you expecting your large area to be a simple polygon (no hole) or a donut (has a hole)?

For 40, do you expect there to be a hole in it (a donut)? If you turn off 90, does 40 continue under it?