+5
Hi all,
I have attributes streets for example below. I want to extract the attribute
14 Le Thanh Nghi >> 14
12B Gia Quat >> 12B
3 Ngach 6 Ngo 12 >> 3
Tran Hung Dao >> Null (Have not number)
Could you tell me how to use regex function to make it?
Thank you
Best answer by markatsafe
View original
+25
If it's always the first part until the space then a regex matching the first word should work:
^\\w+
+5
If it's always the first part until the space then a regex matching the first word should work:
^\\w+
Thank you @Hans van der Maarel .
In the case the street name is "45/11 Tran Hung Dao", It will not get number (Null). Could you tell me what Inverser of
^\\w+ ? because I get the number 14,12B
+25
Thank you @Hans van der Maarel .
In the case the street name is "45/11 Tran Hung Dao", It will not get number (Null). Could you tell me what Inverser of
^\\w+ ? because I get the number 14,12B
The \\w stands for "word character", i.e. letters, numbers and some punctuation, but not spaces or, as it turns out, a /
An alternative would be to use an AttributeSplitter with the space as delimiter character. It'll create a list and _list{0} would be your house number, assuming the data is clean of course. 12 B Gia Quat would result in 12
+2
@hoa_le In StringSearcher use a Regular Expression something like ^([0-9]{1}[0-9a-zA-Z\\w/-]*)\\s.*$
To see how this works go RegExr.com. The () is a subexpression, so in StringSearcher, under Advanced set a Subexpression Matches List Name. "Tran Hung Dao" will come out as Not Matched and you can set the house number to <null> in an AttributeCreator.
I've attached a small example workspace (FME 2020.2)
Try this one:
^\d[\d,\w,/]*It expects the house number to be at the very beginning of the line, and it must be composed of a digit followed by zero or more repetitions of either a digit, a letter or a forward slash.
Try this one:
^\d[\d,\w,/]*It expects the house number to be at the very beginning of the line, and it must be composed of a digit followed by zero or more repetitions of either a digit, a letter or a forward slash.
Alternative:
^\d[\S]*Will return the first "word" of the address, but only if it starts with a digit. Any character is allowed, as long as it's not a space.
+5
Try this one:
^\d[\d,\w,/]*It expects the house number to be at the very beginning of the line, and it must be composed of a digit followed by zero or more repetitions of either a digit, a letter or a forward slash.
In my case, it's perfect for in the above example.
Otherwise, I want to extract:
14 Le Thanh Nghi >> Le Thanh Nghi
12B Gia Quat >> Gia Quat
3 Ngach 6 Ngo 12 >> Ngach 6 Ngo 12
Tran Hung Dao >> Tran Hung Dao
How can I do?
Thank you
+20
In my case, it's perfect for in the above example.
Otherwise, I want to extract:
14 Le Thanh Nghi >> Le Thanh Nghi
12B Gia Quat >> Gia Quat
3 Ngach 6 Ngo 12 >> Ngach 6 Ngo 12
Tran Hung Dao >> Tran Hung Dao
How can I do?
Thank you
Use StringReplacer with RegEx Mode, ^\\d[\\d,\\w,/]*or ^\\d[\\S]* as Text to replace and empty string in Replacement text. That way you just get rig of the number at the beginning.
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