+4
Return XY coordinate of certain Z value along polyline Z
This is not a measure along the line. Measure might be 11200', but z is 10900'. Also, vertices are every 100' or so -- not easy to interpolate to the exact Z via converting the line to vertices. I want to avoid going too complex with this solution -- is there an easy way that is escaping me?
If you can, I think the easiest would be to set the Z-values as measures and use the linear referencing transformers from there.
+25
Close, but no cigar I think... I tried generating contours from the line, then selecting the contour at the Z-value I want and doing a NeighborFinder between that contour and the original line. But the coordinates would be a bit off compared to what I would expect in this case. I expect (5,5) and get (5.02,5.02)
Posting this anyway, maybe it helps.
+4
Close, but no cigar I think... I tried generating contours from the line, then selecting the contour at the Z-value I want and doing a NeighborFinder between that contour and the original line. But the coordinates would be a bit off compared to what I would expect in this case. I expect (5,5) and get (5.02,5.02)
Posting this anyway, maybe it helps.
+25
Hi @setld_solutions
The other thought I had was to cut the line at the elevation that you want the XY of. So I did this:
Basically you have a Creator that creates a polygon covering the x/y area of interest. I made it with a Z value but you could create it with zero Z and use a 3DForcer (publishing the 3DForcer parameter so you get to choose each time where to cut)
The LineOnAreaOverlayer won't work in 3D mode. So... use CoordinateSwappers to swap the X and Z coordinates to get 2D. Do the overlay, switch the coordinates back.
Now I have two lines. The point at which they meet is the X/Y location of the chosen Z value.
If there was a transformer that did 3D intersection the CoordinateSwappers wouldn't be necessary. Sadly I couldn't find one. But it's still a fairly simple solution.
Hope that helps. An interesting problem. I like it.
Mark
+4
Hi @setld_solutions
The other thought I had was to cut the line at the elevation that you want the XY of. So I did this:
Basically you have a Creator that creates a polygon covering the x/y area of interest. I made it with a Z value but you could create it with zero Z and use a 3DForcer (publishing the 3DForcer parameter so you get to choose each time where to cut)
The LineOnAreaOverlayer won't work in 3D mode. So... use CoordinateSwappers to swap the X and Z coordinates to get 2D. Do the overlay, switch the coordinates back.
Now I have two lines. The point at which they meet is the X/Y location of the chosen Z value.
If there was a transformer that did 3D intersection the CoordinateSwappers wouldn't be necessary. Sadly I couldn't find one. But it's still a fairly simple solution.
Hope that helps. An interesting problem. I like it.
Mark
+16
How about this:
Use a Chopper (number of vertices = 2) to create line segments.
Use two MeasureSetter transformers (for start and end point) and set a measure with value @ZValue().
The use the Snipper transfomer with mode Measure(value) to snip at the required Z value.
Finally use the CoordinateExtractor on the End point (index -1) of the Snipped line segment (if needed test for @ZValue = <required value>).
+4
How about this:
Use a Chopper (number of vertices = 2) to create line segments.
Use two MeasureSetter transformers (for start and end point) and set a measure with value @ZValue().
The use the Snipper transfomer with mode Measure(value) to snip at the required Z value.
Finally use the CoordinateExtractor on the End point (index -1) of the Snipped line segment (if needed test for @ZValue = <required value>).
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